Cubes by Bhārati Kṛṣṇa Tīrtha
Introduction
Here we will be learning how to find the cubes of two digit numbers. We will be using the sūtra[1]
आनुरूप्येण
" Ānurūpyeṇa "
" Proportionally "
The detailed steps are explained below .
Let a and b are the two digits .
Step 1 : We will be writing the four numbers in geometric ratio in exact proportion.
First term will be , common ratio =
second term will be
third term will be
fourth term will be
First term | Middle terms (second, third terms) | Fourth term | ||
Step 1 | ||||
Step 2 | double of the middle
terms
|
double of the middle
terms
|
||
Step 3 | add the two middle terms
|
add the two middle terms
|
||
Final Step | https://alpha.indicwiki.in/index.php?title=Special:MathShowImage&hash=7526a2ceceb201826c5fffe6862f928f&mode=mathml | https://alpha.indicwiki.in/index.php?title=Special:MathShowImage&hash=0df1c1fd92d7f7d0a8df80ed2d245d74&mode=mathml | https://alpha.indicwiki.in/index.php?title=Special:MathShowImage&hash=2d275b176c3436e8981c70371f474c9c&mode=mathml |
This is nothing but the expansion of the formula for where a and b are two individual digits of the number. This will makes the calculation of cubes very fast and easy. This will be explained through the below examples.
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
---|---|---|---|---|---|---|---|---|
1 | 8 | 27 | 64 | 125 | 216 | 343 | 512 | 729 |
Example: 233
Here a = 2 , b = 3 , Using the final step mentioned above.
23 = 8 | 3 X ( 22 X 3) = 3 (4 X 3) | 3 X (2 X 32) = 3 X (2 X 9) | 33 = 27 |
8 | 36 | 54 | 27 |
8 | 36 | 54 | Put 7 and carry over 2 |
8 | 36 | 54 + Carry over (2) | 7 |
8 | 36 | 56 | 7 |
8 | 36 | Put 6 and carry over 5 | 7 |
8 | 36 + Carry over (5) | 6 | 7 |
8 | 41 | 6 | 7 |
8 | Put 1 and carry over 4 | 6 | 7 |
8 + Carry over (4) | 1 | 6 | 7 |
12 | 1 | 6 | 7 |
Answer : 233 = 12167
Example: 123
Here a = 1 , b = 2 , Using the final step mentioned above.
13 = 1 | 3 X ( 12 X 2) = 3 (1 X 2) | 3 X (1 X 22) = 3 X (1 X 4) | 23 = 8 |
1 | 6 | 12 | 8 |
1 | 6 | Put 2 and carry over 1 | 8 |
1 | 6 + Carry over (1) | 2 | 8 |
1 | 7 | 2 | 8 |
Answer : 123 = 1728
Example: 253
Here a = 2, b = 5 , Using the final step mentioned above.
23 = 8 | 3 X ( 22 X 5) = 3 (4 X 5) | 3 X (2 X 52) = 3 X (2 X 25) | 53 = 125 |
8 | 60 | 150 | 125 |
8 | 60 | 150 | Put 5 and carry over 12 |
8 | 60 | 150 + Carry over (12) | 5 |
8 | 60 | 162 | 5 |
8 | 60 | Put 2 and carry over 16 | 5 |
8 | 60 + Carry over (16) | 2 | 5 |
8 | 76 | 2 | 5 |
8 | Put 6 and carry over 7 | 2 | 5 |
8 + Carry over (7) | 6 | 2 | 5 |
15 | 6 | 2 | 5 |
Answer : 253 = 15625
See Also
References
- ↑ Singhal, Vandana (2007). Vedic Mathematics For All Ages - A Beginners' Guide. Delhi: Motilal Banarsidass. pp. 237–242. ISBN 978-81-208-3230-5.